What is the total number of standard 12 x 12 tiles required to cover an 8' ceiling measuring 13'-7" by 20'-8"?

To determine the total number of standard 12 x 12 tiles required to cover a ceiling measuring 13'-7" by 20'-8", it's important to first convert the ceiling dimensions into inches for easier calculations.

1. Convert the dimensions:

• 13 feet 7 inches = (13 x 12) + 7 = 156 + 7 = 163 inches

• 20 feet 8 inches = (20 x 12) + 8 = 240 + 8 = 248 inches

2. Calculate the area of the ceiling:

• Area = length x width = 163 inches x 248 inches = 40484 square inches

3. Calculate the area of a standard 12 x 12 tile:

• Area of tile = 12 inches x 12 inches = 144 square inches

4. Calculate the number of tiles needed:

• Total number of tiles = Total area of the ceiling ÷ Area of one tile

• Total number of tiles = 40484 square inches ÷ 144 square inches = 281.43 tiles

Since you cannot have a fraction of a tile, you would need to round up. Therefore, you need 282 tiles